Thread: [PI]Object distance check

Bump

Originally Posted by BryceTheCoder

Here is a function I like called goodDistance(int, int, int, int, int);
However, if you have a PI base you probably have it already inside your Player class.

Here is the function:

Code:

public boolean goodDistance(int objectX, int objectY, int playerX,
			int playerY, int distance) {
		for (int i = 0; i <= distance; i++) {
			for (int j = 0; j <= distance; j++) {
				if ((objectX + i) == playerX
						&& ((objectY + j) == playerY
						|| (objectY - j) == playerY || objectY == playerY)) {
					return true;
				} else if ((objectX - i) == playerX
						&& ((objectY + j) == playerY
						|| (objectY - j) == playerY || objectY == playerY)) {
					return true;
				} else if (objectX == playerX
						&& ((objectY + j) == playerY
						|| (objectY - j) == playerY || objectY == playerY)) {
					return true;
				}
			}
		}
		return false;
	}

So, now you can imagine how you use it.
For example, you want the players to be close to the range before executing "Cooking".
On the packet of where the player uses the item on the range, do a simple if statement like:

Code:

if (goodDistance(objectX, objectY, c.absX, c.absY, DistanceYouDesire)) {
//DoCooking();
}

This will do a simple if statement check to see if the player is within "DistanceYouDesire" tiles with the object.

Hope I helped

And distance i desire is just the amount of tiles away?

Originally Posted by BryceTheCoder

Here is a function I like called goodDistance(int, int, int, int, int);
However, if you have a PI base you probably have it already inside your Player class.

Here is the function:

Code:

public boolean goodDistance(int objectX, int objectY, int playerX,
			int playerY, int distance) {
		for (int i = 0; i <= distance; i++) {
			for (int j = 0; j <= distance; j++) {
				if ((objectX + i) == playerX
						&& ((objectY + j) == playerY
						|| (objectY - j) == playerY || objectY == playerY)) {
					return true;
				} else if ((objectX - i) == playerX
						&& ((objectY + j) == playerY
						|| (objectY - j) == playerY || objectY == playerY)) {
					return true;
				} else if (objectX == playerX
						&& ((objectY + j) == playerY
						|| (objectY - j) == playerY || objectY == playerY)) {
					return true;
				}
			}
		}
		return false;
	}

This will do a simple if statement check to see if the player is within "DistanceYouDesire" tiles with the object.

Hope I helped

Couldn't you just replace that whole method with 1 if statement?

Code:

public boolean goodDistance(int objectX, int objectY, int playerX, int playerY, int distance) {
   if (((playerX + playerY) - (objectX + objectY)) <= distance && ((objectX + objectY) - (playerX + playerY) <= distance)) {
      return true;
   } else {
         return false;
      }
}

Of course this might be a bit cleaner:

Code:

public boolean goodDistance(int objectX, int objectY, int playerX, int playerY, int distance) {
   
   int objSum = objectX + objectY;
   int playerSum = playerX + playerY;
   if (playerSum - objSum <= distance && objSum - playerSum <= distance) {
      return true;
   } else {
         return false;
      }   
}

maybe ternary?

Code:

public boolean goodDistance(int objectX, int objectY, int playerX, int playerY, int distance) {
   int firstDif = (playerX + playerY) - (objectX + objectY);
   int secDif = (objectX + objectY) - (playerX + playerY);
      boolean result = (firstDif <= distance && secDif <= distance) ? true : false;
      return result;
}

These are untested though, may not work lol.

Originally Posted by BryceTheCoder

Here is a function I like called goodDistance(int, int, int, int, int);
However, if you have a PI base you probably have it already inside your Player class.

Here is the function:

Code:

public boolean goodDistance(int objectX, int objectY, int playerX,
			int playerY, int distance) {
		for (int i = 0; i <= distance; i++) {
			for (int j = 0; j <= distance; j++) {
				if ((objectX + i) == playerX
						&& ((objectY + j) == playerY
						|| (objectY - j) == playerY || objectY == playerY)) {
					return true;
				} else if ((objectX - i) == playerX
						&& ((objectY + j) == playerY
						|| (objectY - j) == playerY || objectY == playerY)) {
					return true;
				} else if (objectX == playerX
						&& ((objectY + j) == playerY
						|| (objectY - j) == playerY || objectY == playerY)) {
					return true;
				}
			}
		}
		return false;
	}

So, now you can imagine how you use it.
For example, you want the players to be close to the range before executing "Cooking".
On the packet of where the player uses the item on the range, do a simple if statement like:

Code:

if (goodDistance(objectX, objectY, c.absX, c.absY, DistanceYouDesire)) {
//DoCooking();
}

This will do a simple if statement check to see if the player is within "DistanceYouDesire" tiles with the object.

Hope I helped

Getting a error when compiling..

src\server\model\players\packets\ItemOnObject.java :55: error: cannot find symbol

if (goodDistance(objectX, objectY, c.absX, c.absY, 2)) {

^
symbol: method goodDistance(int,int,int,int,int)
location: class ItemOnObject
1 error
Press any key to continue . . .