Hey guys, I am currently creating a website and I am having some trouble, here is my problem
Code:
Parse error: syntax error, unexpected ';' in /home/a1558487/public_html/VisualUpload/func/user.func.php on line 10
and here is the file
Code:
<?php
function logged_in() {
return isset($_SESSION['user_id']);
}
function login_check($email, $password) {
$email = mysql_real_escape_string($email);
$login_query = mysql_query("SELECT COUNT('user_id') as 'count', 'user_id' FROM 'users' WHERE 'email'='$email' AND 'password'='".md5($password."'");
return (mysql_result($login_query, 0) == 1) ? mysql_result($login_query, 0, 'user_id') : false;
}
function user_data() {
$args = func_get_args();
$fields = '`'.implode('`, ', $args).'`';
$query = mysql_query("SELECT $fields FROM 'users' WHERE 'user_id'=".$_SESSION['user_id']);
$query_result = mysql_fetch_assoc($query);
foreach ($args as $field) {
$args[$field] = $query_result[$field];
}
return $args;
}
function user_register($email, $name, $password) {
$email = mysql_real_escape_string($email);
$name = mysql_real_escape_string($name);
mysql_query("INSERT INTO 'users' VALUES ('', '$email', '$name', '".md5($password)."')");
return mysql_insert_id();
}
function user_exists($email) {
$email = mysql_real_escape_string($email);
$query = mysql_query("SELECT COUNT('user_id') FROM 'users' WHERE 'email'='$email'");
return (mysql_result($query, 0) == 1) ? true : false;
}
?>
I hope someone can please help