Finding the number of unique values for a 2 dimensional array

Hey guys, does anyone know how to find the number of unique values in a 2 dimensional array.

For example: an array containing the numbers 1, 2, 3, 4, 4, 2, 3 would have 4 unique values.

Thanks.

Code:

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public int getUniqueValues(List<Integer> integers) {
    List<Integer> alreadyUsed = new LinkedList<Integer>();
    int unique = 0;
    for (Integer i : integers) {
        if (!alreadyUsed.contains(i)) {
            alreadyUsed.add(i);
            ++unique;
        }
    }
    return unique;
}

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or somethin

---------- Post added at 01:52 AM ---------- Previous post was at 01:43 AM ----------

Code:

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>>> def getunique(integers):
...    used = []
...    unique = 0
...    for i in integers:
...        if used.count(i) == 0:
...            used.append(i)
...            unique=unique+1
...    return unique
...
>>> getunique([1, 2, 3, 4, 4, 2, 3])
4
>>>

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shud work

Code:

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    public void getUniqueValues(int[][] integers) {
        ArrayList vals = new ArrayList();
        for (int i = 0; i < integers.length; i++) {
            for (int i2 = 0; i2 < integers[i].length; i2++) {
                if (!vals.contains(integers[i][i2])) {
                    vals.add(integers[i][i2]);
                    System.out.println(integers[i][i2]);
                }
            }
        }
    }

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It might outprint 0 even if you didn't put it in the array, that's because when you initialize the array, all spots that aren't filled have values of 0

Thanks for your help, but i figured it out already. I just converted it to a 1D array and found the uniques from there.

Quote:

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Originally Posted by _Anthony [Only registered and activated users can see links. Click Here To Register...]

Code:

---

    public void getUniqueValues(int[][] integers) {
        ArrayList vals = new ArrayList();
        for (int i = 0; i < integers.length; i++) {
            for (int i2 = 0; i2 < integers[i].length; i2++) {
                if (!vals.contains(integers[i][i2])) {
                    vals.add(integers[i][i2]);
                    System.out.println(integers[i][i2]);
                }
            }
        }
    }

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It might outprint 0 even if you didn't put it in the array, that's because when you initialize the array, all spots that aren't filled have values of 0

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ewwww... learn to use generics