Help with this trig homework pelase
https://i.imgur.com/D6QCeRM.png
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Use this to help you out.
Soh Cah Toa
Sin = opposite/hypothenuse
Cos - adjacent/hypothenuse
Tan = opposite / adjacent
And the theta would be the opposite of whatever i provided on the top. So just plug in the numbers.
Opposite = 4
Hypotenuse = 7
Adjacent = 8
For the 3rd side, it'll be 7^2 + 4^2 = 64 and the square root would be 8 because 8 * 8 = 64
Hope this helped
The Pythagorean Theorem states that the square of the hypotenuse is equal to the sum of the squares of the other two sides. The equation should then be written as...
...where 'a' is representing the side unmarked. To simplify this equation in one step (I can supply all of the steps, if necessary), the equation would then look like this...Code:a^2 + 4^2 = 7^2
...then making side 'a' equal to the square root of 33. You could simplify further to clean up the square root but I usually only took this step if the professor required it. Now that you have all of the side lengths, you can begin performing the six trigonometric functions using the SOH (sin = opposite / hypotenuse) CAH (cos = adjacent / hypotenuse) TOA (tan = opposite / adjacent) method, as mentioned above. If you need any more help, I am happy to elaborate.Code:a^2 = 33
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