Thread: Math [Linear Equation help]

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  1. #1 Math [Linear Equation help] 
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    Basically, i'm not really asking for an answer, partially because graphing is involved, but i mean if you're willing to graph by all means please do lol.



    If you could just give me a few steps on how to solve this I would be very greatful. thank you
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    Registered Member p o e's Avatar
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    lol
    1) Draw a line that goes from 12 on the Y axis to 15 on the X axis
    2) Draw a line that goes from -4.55 on the Y axis to 4.134 on the X axis
    3) Profit

    EDIT: oops

    at equilibrium, the p value of both lines are equal, so
    12- 0.8q = -4.55 + 1.1q
    16.55 = 1.9q
    q = 8.71
    p = 12 - 0.8(8.71)
    p = 5.03
    Last edited by p o e; 09-09-2014 at 12:16 PM. Reason: lol misred ok
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    Dan
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    Position of equilibrium when buyer and seller agrees on price.
    So I guess you find when both equations have same y coord.
    Solve 12-0.8q = 4.55 +1.1q
    q = 3.92105 (this is x coord)

    Plug into either equation
    12-.8(3.92105) = y
    y= 8.86316

    Equilibrium point at (3.92, 8.86)

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    Quote Originally Posted by +dan View Post
    Position of equilibrium when buyer and seller agrees on price.
    So I guess you find when both equations have same y coord.
    Solve 12-0.8q = 4.55 +1.1q
    q = 3.92105 (this is x coord)

    Plug into either equation
    12-.8(3.92105) = y
    y= 8.86316

    Equilibrium point at (3.92, 8.86)

    The second graph has a y intercept of -4.55, not 4.55
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