How do i find x using factorization
2x^2+3x-35=0
Thanks
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How do i find x using factorization
2x^2+3x-35=0
Thanks
2x^2 - 3x - 35= 0
Factoring: 2x^2 - 10x +7x -35 = 0
(2x^2 -10x) + (7x -35) = 0
2x(x-5) + 7(x-5) = 0
(x-5)(2x+7) = 0
x = {-7/2, 5}
Here's your problem explained: Solve 2x^2-3x-35=0
Enjoy !
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