Thread: Basic Integraton of Logs

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  1. #1 Basic Integraton of Logs 
    Registered Member Lust's Avatar
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    Can someone show me how to do this? I have a test tomorrow and I'm lost.

    ∫ (ln x) ^2/x in terms of x(dx)


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    Mister Maggot's Avatar
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    So you've got

    ∫(ln(x)^2)/x

    that's awesome since d/dx=1/x and it can be simplified as (u^2)du if your u is ln(x) and du is 1/x

    now

    ∫u^2du = ((u^3)/3)+C

    or

    ((ln(x)^3)/3)+C
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  4. #3  
    Registered Member Lust's Avatar
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    Quote Originally Posted by Mister Maggot View Post
    So you've got

    ∫(ln(x)^2)/x

    that's awesome since d/dx=1/x and it can be simplified as (u^2)du if your u is ln(x) and du is 1/x

    now

    ∫u^2du = ((u^3)/3)+C

    or

    ((ln(x)^3)/3)+C

    thanks for helping me out there, i think you probably saved my test grade.


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