Hello, I'm too tired to solve this equation, can someone help me?
Code:x^2 + (2i -3)*x + 5 - i = 0
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11-24-2010, 09:16 PM
Hello, I'm too tired to solve this equation, can someone help me?
Code:x^2 + (2i -3)*x + 5 - i = 0
ok, here is a hint; x = a +bi with a,b \in R
start by substituting x=(a+bi), expand the square, and then separate the equation into two equations. say you get f(a,b) = 0. then your new equation system is Im{f(a,b)} = 0 and Re{f(a,b)} = 0.
x² + (2i-3)x + 5 - i = 0Originally Posted by Tholgard
Looks like a quadratic
D = b²-4ac
= (2i-3)² - 4*(5-i)
= -4 - 12i + 9 - 20 + 4i
= -15 -8i
Answers are :
(-+(2i-3) +- sqrt( -15-8i))/2
= 2 - 3i and -2 + 3i
rep pl0xxxxxx
I'm a senior in high school and I feel stupid because I don't know how to do any of this. lmao.
Originally Posted by Swarfega
you must also feel stupid for having faith
If he can't even solve this. I agree.
Why cant i thank this.
thsi is old now?
anways correct answer:
x=0,3-2i
Q3MDVK56GGJ
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